2x^2+32x=34

Solution for 2x^2+32x=34 equation:

2x^2+32x=34

We move all terms to the left:

2x^2+32x-(34)=0

a = 2; b = 32; c = -34;
Δ = b2-4ac
Δ = 322-4·2·(-34)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-36}{2*2}=\frac{-68}{4}
=-17
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+36}{2*2}=\frac{4}{4}
=1
$